8(2x-5)+10=3(6x-2)

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Solution for 8(2x-5)+10=3(6x-2) equation: 



8(2x-5)+10=3(6x-2)

We move all terms to the left:

8(2x-5)+10-(3(6x-2))=0

We multiply parentheses

16x-(3(6x-2))-40+10=0



We calculate terms in parentheses: -(3(6x-2)), so:

3(6x-2)

We multiply parentheses

18x-6

Back to the equation:

-(18x-6)



We add all the numbers together, and all the variables

16x-(18x-6)-30=0

We get rid of parentheses

16x-18x+6-30=0

We add all the numbers together, and all the variables

-2x-24=0

We move all terms containing x to the left, all other terms to the right

-2x=24

x=24/-2

x=-12

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