8(2x-5)=16x-36-x

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Solution for 8(2x-5)=16x-36-x equation: 



8(2x-5)=16x-36-x

We move all terms to the left:

8(2x-5)-(16x-36-x)=0

We add all the numbers together, and all the variables

8(2x-5)-(15x-36)=0

We multiply parentheses

16x-(15x-36)-40=0

We get rid of parentheses

16x-15x+36-40=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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