8(2x-5)=2(3x-4)

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Solution for 8(2x-5)=2(3x-4) equation:



8(2x-5)=2(3x-4)
We move all terms to the left:
8(2x-5)-(2(3x-4))=0
We multiply parentheses
16x-(2(3x-4))-40=0
We calculate terms in parentheses: -(2(3x-4)), so:
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
We get rid of parentheses
16x-6x+8-40=0
We add all the numbers together, and all the variables
10x-32=0
We move all terms containing x to the left, all other terms to the right
10x=32
x=32/10
x=3+1/5

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