8(2x-5)=2(8x+1)

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Solution for 8(2x-5)=2(8x+1) equation:


Simplifying
8(2x + -5) = 2(8x + 1)

Reorder the terms:
8(-5 + 2x) = 2(8x + 1)
(-5 * 8 + 2x * 8) = 2(8x + 1)
(-40 + 16x) = 2(8x + 1)

Reorder the terms:
-40 + 16x = 2(1 + 8x)
-40 + 16x = (1 * 2 + 8x * 2)
-40 + 16x = (2 + 16x)

Add '-16x' to each side of the equation.
-40 + 16x + -16x = 2 + 16x + -16x

Combine like terms: 16x + -16x = 0
-40 + 0 = 2 + 16x + -16x
-40 = 2 + 16x + -16x

Combine like terms: 16x + -16x = 0
-40 = 2 + 0
-40 = 2

Solving
-40 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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