8(2x-5)=4(1-3x)

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Solution for 8(2x-5)=4(1-3x) equation: 



8(2x-5)=4(1-3x)

We move all terms to the left:

8(2x-5)-(4(1-3x))=0

We add all the numbers together, and all the variables

8(2x-5)-(4(-3x+1))=0

We multiply parentheses

16x-(4(-3x+1))-40=0



We calculate terms in parentheses: -(4(-3x+1)), so:

4(-3x+1)

We multiply parentheses

-12x+4

Back to the equation:

-(-12x+4)



We get rid of parentheses

16x+12x-4-40=0

We add all the numbers together, and all the variables

28x-44=0

We move all terms containing x to the left, all other terms to the right

28x=44

x=44/28

x=1+4/7

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