8(2x-5)=6(x-2)

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Solution for 8(2x-5)=6(x-2) equation: 



8(2x-5)=6(x-2)

We move all terms to the left:

8(2x-5)-(6(x-2))=0

We multiply parentheses

16x-(6(x-2))-40=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

16x-6x+12-40=0

We add all the numbers together, and all the variables

10x-28=0

We move all terms containing x to the left, all other terms to the right

10x=28

x=28/10

x=2+4/5

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