8(2x-5)=7(3x+1)

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Solution for 8(2x-5)=7(3x+1) equation:


Simplifying
8(2x + -5) = 7(3x + 1)

Reorder the terms:
8(-5 + 2x) = 7(3x + 1)
(-5 * 8 + 2x * 8) = 7(3x + 1)
(-40 + 16x) = 7(3x + 1)

Reorder the terms:
-40 + 16x = 7(1 + 3x)
-40 + 16x = (1 * 7 + 3x * 7)
-40 + 16x = (7 + 21x)

Solving
-40 + 16x = 7 + 21x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-21x' to each side of the equation.
-40 + 16x + -21x = 7 + 21x + -21x

Combine like terms: 16x + -21x = -5x
-40 + -5x = 7 + 21x + -21x

Combine like terms: 21x + -21x = 0
-40 + -5x = 7 + 0
-40 + -5x = 7

Add '40' to each side of the equation.
-40 + 40 + -5x = 7 + 40

Combine like terms: -40 + 40 = 0
0 + -5x = 7 + 40
-5x = 7 + 40

Combine like terms: 7 + 40 = 47
-5x = 47

Divide each side by '-5'.
x = -9.4

Simplifying
x = -9.4

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