8(2x-5)=8(2x)-8(5)=16x-40

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Solution for 8(2x-5)=8(2x)-8(5)=16x-40 equation: 



8(2x-5)=8(2x)-8(5)=16x-40

We move all terms to the left:

8(2x-5)-(8(2x)-8(5))=0

We multiply parentheses

16x-(82x-85)-40=0

We get rid of parentheses

16x-82x+85-40=0

We add all the numbers together, and all the variables

-66x+45=0

We move all terms containing x to the left, all other terms to the right

-66x=-45

x=-45/-66

x=15/22

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