8(2x-6)-2=8(x-5)+6

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Solution for 8(2x-6)-2=8(x-5)+6 equation: 



8(2x-6)-2=8(x-5)+6

We move all terms to the left:

8(2x-6)-2-(8(x-5)+6)=0

We multiply parentheses

16x-(8(x-5)+6)-48-2=0



We calculate terms in parentheses: -(8(x-5)+6), so:

8(x-5)+6

We multiply parentheses

8x-40+6

We add all the numbers together, and all the variables

8x-34

Back to the equation:

-(8x-34)



We add all the numbers together, and all the variables

16x-(8x-34)-50=0

We get rid of parentheses

16x-8x+34-50=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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