8(2x-9)=3(3x+12)

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Solution for 8(2x-9)=3(3x+12) equation: 



8(2x-9)=3(3x+12)

We move all terms to the left:

8(2x-9)-(3(3x+12))=0

We multiply parentheses

16x-(3(3x+12))-72=0



We calculate terms in parentheses: -(3(3x+12)), so:

3(3x+12)

We multiply parentheses

9x+36

Back to the equation:

-(9x+36)



We get rid of parentheses

16x-9x-36-72=0

We add all the numbers together, and all the variables

7x-108=0

We move all terms containing x to the left, all other terms to the right

7x=108

x=108/7

x=15+3/7

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