8(2y+3)+7=4(y-3)+19

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Solution for 8(2y+3)+7=4(y-3)+19 equation:



8(2y+3)+7=4(y-3)+19
We move all terms to the left:
8(2y+3)+7-(4(y-3)+19)=0
We multiply parentheses
16y-(4(y-3)+19)+24+7=0
We calculate terms in parentheses: -(4(y-3)+19), so:
4(y-3)+19
We multiply parentheses
4y-12+19
We add all the numbers together, and all the variables
4y+7
Back to the equation:
-(4y+7)
We add all the numbers together, and all the variables
16y-(4y+7)+31=0
We get rid of parentheses
16y-4y-7+31=0
We add all the numbers together, and all the variables
12y+24=0
We move all terms containing y to the left, all other terms to the right
12y=-24
y=-24/12
y=-2

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