8(2y+3)+7=4(y-3)+19

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Solution for 8(2y+3)+7=4(y-3)+19 equation: 



8(2y+3)+7=4(y-3)+19

We move all terms to the left:

8(2y+3)+7-(4(y-3)+19)=0

We multiply parentheses

16y-(4(y-3)+19)+24+7=0



We calculate terms in parentheses: -(4(y-3)+19), so:

4(y-3)+19

We multiply parentheses

4y-12+19

We add all the numbers together, and all the variables

4y+7

Back to the equation:

-(4y+7)



We add all the numbers together, and all the variables

16y-(4y+7)+31=0

We get rid of parentheses

16y-4y-7+31=0

We add all the numbers together, and all the variables

12y+24=0

We move all terms containing y to the left, all other terms to the right

12y=-24

y=-24/12

y=-2

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