8(2y-2)=7(3y-2)

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Solution for 8(2y-2)=7(3y-2) equation: 



8(2y-2)=7(3y-2)

We move all terms to the left:

8(2y-2)-(7(3y-2))=0

We multiply parentheses

16y-(7(3y-2))-16=0



We calculate terms in parentheses: -(7(3y-2)), so:

7(3y-2)

We multiply parentheses

21y-14

Back to the equation:

-(21y-14)



We get rid of parentheses

16y-21y+14-16=0

We add all the numbers together, and all the variables

-5y-2=0

We move all terms containing y to the left, all other terms to the right

-5y=2

y=2/-5

y=-2/5

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