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8(2y-4)=10+(7y+3)
We move all terms to the left:
8(2y-4)-(10+(7y+3))=0
We multiply parentheses
16y-(10+(7y+3))-32=0
We calculate terms in parentheses: -(10+(7y+3)), so:We get rid of parentheses
10+(7y+3)
determiningTheFunctionDomain (7y+3)+10
We get rid of parentheses
7y+3+10
We add all the numbers together, and all the variables
7y+13
Back to the equation:
-(7y+13)
16y-7y-13-32=0
We add all the numbers together, and all the variables
9y-45=0
We move all terms containing y to the left, all other terms to the right
9y=45
y=45/9
y=5
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