8(2y-4)=10+(7y+3)

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Solution for 8(2y-4)=10+(7y+3) equation: 



8(2y-4)=10+(7y+3)

We move all terms to the left:

8(2y-4)-(10+(7y+3))=0

We multiply parentheses

16y-(10+(7y+3))-32=0



We calculate terms in parentheses: -(10+(7y+3)), so:

10+(7y+3)

determiningTheFunctionDomain
(7y+3)+10

We get rid of parentheses

7y+3+10

We add all the numbers together, and all the variables

7y+13

Back to the equation:

-(7y+13)



We get rid of parentheses

16y-7y-13-32=0

We add all the numbers together, and all the variables

9y-45=0

We move all terms containing y to the left, all other terms to the right

9y=45

y=45/9

y=5

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