8(2y-5)=6(3y-7)+1

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Solution for 8(2y-5)=6(3y-7)+1 equation: 



8(2y-5)=6(3y-7)+1

We move all terms to the left:

8(2y-5)-(6(3y-7)+1)=0

We multiply parentheses

16y-(6(3y-7)+1)-40=0



We calculate terms in parentheses: -(6(3y-7)+1), so:

6(3y-7)+1

We multiply parentheses

18y-42+1

We add all the numbers together, and all the variables

18y-41

Back to the equation:

-(18y-41)



We get rid of parentheses

16y-18y+41-40=0

We add all the numbers together, and all the variables

-2y+1=0

We move all terms containing y to the left, all other terms to the right

-2y=-1

y=-1/-2

y=1/2

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