8(2z-1)=10(z+2)

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Solution for 8(2z-1)=10(z+2) equation: 



8(2z-1)=10(z+2)

We move all terms to the left:

8(2z-1)-(10(z+2))=0

We multiply parentheses

16z-(10(z+2))-8=0



We calculate terms in parentheses: -(10(z+2)), so:

10(z+2)

We multiply parentheses

10z+20

Back to the equation:

-(10z+20)



We get rid of parentheses

16z-10z-20-8=0

We add all the numbers together, and all the variables

6z-28=0

We move all terms containing z to the left, all other terms to the right

6z=28

z=28/6

z=4+2/3

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