8(2z-1)=10(z+2)

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Solution for 8(2z-1)=10(z+2) equation:



8(2z-1)=10(z+2)
We move all terms to the left:
8(2z-1)-(10(z+2))=0
We multiply parentheses
16z-(10(z+2))-8=0
We calculate terms in parentheses: -(10(z+2)), so:
10(z+2)
We multiply parentheses
10z+20
Back to the equation:
-(10z+20)
We get rid of parentheses
16z-10z-20-8=0
We add all the numbers together, and all the variables
6z-28=0
We move all terms containing z to the left, all other terms to the right
6z=28
z=28/6
z=4+2/3

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