8(2z-5)=27+13

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Solution for 8(2z-5)=27+13 equation: 



8(2z-5)=27+13

We move all terms to the left:

8(2z-5)-(27+13)=0

We add all the numbers together, and all the variables

8(2z-5)-40=0

We multiply parentheses

16z-40-40=0

We add all the numbers together, and all the variables

16z-80=0

We move all terms containing z to the left, all other terms to the right

16z=80

z=80/16

z=5

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