8(3+2x)-4=17+5(x-17)+22

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Solution for 8(3+2x)-4=17+5(x-17)+22 equation: 



8(3+2x)-4=17+5(x-17)+22

We move all terms to the left:

8(3+2x)-4-(17+5(x-17)+22)=0

We add all the numbers together, and all the variables

8(2x+3)-(17+5(x-17)+22)-4=0

We multiply parentheses

16x-(17+5(x-17)+22)+24-4=0



We calculate terms in parentheses: -(17+5(x-17)+22), so:

17+5(x-17)+22

determiningTheFunctionDomain
5(x-17)+17+22

We add all the numbers together, and all the variables

5(x-17)+39

We multiply parentheses

5x-85+39

We add all the numbers together, and all the variables

5x-46

Back to the equation:

-(5x-46)



We add all the numbers together, and all the variables

16x-(5x-46)+20=0

We get rid of parentheses

16x-5x+46+20=0

We add all the numbers together, and all the variables

11x+66=0

We move all terms containing x to the left, all other terms to the right

11x=-66

x=-66/11

x=-6

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