8(3+b+1)=4(b+3)-9

Solution for 8(3+b+1)=4(b+3)-9 equation:

Simplifying
8(3 + b + 1) = 4(b + 3) + -9

Reorder the terms:
8(3 + 1 + b) = 4(b + 3) + -9

Combine like terms: 3 + 1 = 4
8(4 + b) = 4(b + 3) + -9
(4 * 8 + b * 8) = 4(b + 3) + -9
(32 + 8b) = 4(b + 3) + -9

Reorder the terms:
32 + 8b = 4(3 + b) + -9
32 + 8b = (3 * 4 + b * 4) + -9
32 + 8b = (12 + 4b) + -9

Reorder the terms:
32 + 8b = 12 + -9 + 4b

Combine like terms: 12 + -9 = 3
32 + 8b = 3 + 4b

Solving
32 + 8b = 3 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
32 + 8b + -4b = 3 + 4b + -4b

Combine like terms: 8b + -4b = 4b
32 + 4b = 3 + 4b + -4b

Combine like terms: 4b + -4b = 0
32 + 4b = 3 + 0
32 + 4b = 3

Add '-32' to each side of the equation.
32 + -32 + 4b = 3 + -32

Combine like terms: 32 + -32 = 0
0 + 4b = 3 + -32
4b = 3 + -32

Combine like terms: 3 + -32 = -29
4b = -29

Divide each side by '4'.
b = -7.25

Simplifying
b = -7.25