8(3+c)=4(3+c)

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Solution for 8(3+c)=4(3+c) equation: 



8(3+c)=4(3+c)

We move all terms to the left:

8(3+c)-(4(3+c))=0

We add all the numbers together, and all the variables

8(c+3)-(4(c+3))=0

We multiply parentheses

8c-(4(c+3))+24=0



We calculate terms in parentheses: -(4(c+3)), so:

4(c+3)

We multiply parentheses

4c+12

Back to the equation:

-(4c+12)



We get rid of parentheses

8c-4c-12+24=0

We add all the numbers together, and all the variables

4c+12=0

We move all terms containing c to the left, all other terms to the right

4c=-12

c=-12/4

c=-3

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