8(3+c)=7(5+c)

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Solution for 8(3+c)=7(5+c) equation:



8(3+c)=7(5+c)
We move all terms to the left:
8(3+c)-(7(5+c))=0
We add all the numbers together, and all the variables
8(c+3)-(7(c+5))=0
We multiply parentheses
8c-(7(c+5))+24=0
We calculate terms in parentheses: -(7(c+5)), so:
7(c+5)
We multiply parentheses
7c+35
Back to the equation:
-(7c+35)
We get rid of parentheses
8c-7c-35+24=0
We add all the numbers together, and all the variables
c-11=0
We move all terms containing c to the left, all other terms to the right
c=11

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