8(3+c)=7(5+c)

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Solution for 8(3+c)=7(5+c) equation: 



8(3+c)=7(5+c)

We move all terms to the left:

8(3+c)-(7(5+c))=0

We add all the numbers together, and all the variables

8(c+3)-(7(c+5))=0

We multiply parentheses

8c-(7(c+5))+24=0



We calculate terms in parentheses: -(7(c+5)), so:

7(c+5)

We multiply parentheses

7c+35

Back to the equation:

-(7c+35)



We get rid of parentheses

8c-7c-35+24=0

We add all the numbers together, and all the variables

c-11=0

We move all terms containing c to the left, all other terms to the right

c=11

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