8(3+y)=4(y-6)

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Solution for 8(3+y)=4(y-6) equation: 



8(3+y)=4(y-6)

We move all terms to the left:

8(3+y)-(4(y-6))=0

We add all the numbers together, and all the variables

8(y+3)-(4(y-6))=0

We multiply parentheses

8y-(4(y-6))+24=0



We calculate terms in parentheses: -(4(y-6)), so:

4(y-6)

We multiply parentheses

4y-24

Back to the equation:

-(4y-24)



We get rid of parentheses

8y-4y+24+24=0

We add all the numbers together, and all the variables

4y+48=0

We move all terms containing y to the left, all other terms to the right

4y=-48

y=-48/4

y=-12

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