8(3-(4+6x))-2x=-10+2(1-25x)

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Solution for 8(3-(4+6x))-2x=-10+2(1-25x) equation: 



8(3-(4+6x))-2x=-10+2(1-25x)

We move all terms to the left:

8(3-(4+6x))-2x-(-10+2(1-25x))=0

We add all the numbers together, and all the variables

8(3-(6x+4))-2x-(-10+2(-25x+1))=0

We add all the numbers together, and all the variables

-2x+8(3-(6x+4))-(-10+2(-25x+1))=0



We calculate terms in parentheses: -(-10+2(-25x+1)), so:

-10+2(-25x+1)

determiningTheFunctionDomain
2(-25x+1)-10

We multiply parentheses

-50x+2-10

We add all the numbers together, and all the variables

-50x-8

Back to the equation:

-(-50x-8)



We get rid of parentheses

-2x+8(3-(6x+4))+50x+8=0

We add all the numbers together, and all the variables

48x+8(3-(6x+4))+8=0

We move all terms containing x to the left, all other terms to the right

48x+8(3-(6x+4))=-8

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