8(3-(5+6x))-4x=-18+2(1-26x)

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Solution for 8(3-(5+6x))-4x=-18+2(1-26x) equation: 



8(3-(5+6x))-4x=-18+2(1-26x)

We move all terms to the left:

8(3-(5+6x))-4x-(-18+2(1-26x))=0

We add all the numbers together, and all the variables

8(3-(6x+5))-4x-(-18+2(-26x+1))=0

We add all the numbers together, and all the variables

-4x+8(3-(6x+5))-(-18+2(-26x+1))=0



We calculate terms in parentheses: -(-18+2(-26x+1)), so:

-18+2(-26x+1)

determiningTheFunctionDomain
2(-26x+1)-18

We multiply parentheses

-52x+2-18

We add all the numbers together, and all the variables

-52x-16

Back to the equation:

-(-52x-16)



We get rid of parentheses

-4x+8(3-(6x+5))+52x+16=0

We add all the numbers together, and all the variables

48x+8(3-(6x+5))+16=0

We move all terms containing x to the left, all other terms to the right

48x+8(3-(6x+5))=-16

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