8(3-2b)=-2(3+2b)-6b

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Solution for 8(3-2b)=-2(3+2b)-6b equation:



8(3-2b)=-2(3+2b)-6b
We move all terms to the left:
8(3-2b)-(-2(3+2b)-6b)=0
We add all the numbers together, and all the variables
8(-2b+3)-(-2(2b+3)-6b)=0
We multiply parentheses
-16b-(-2(2b+3)-6b)+24=0
We calculate terms in parentheses: -(-2(2b+3)-6b), so:
-2(2b+3)-6b
We add all the numbers together, and all the variables
-6b-2(2b+3)
We multiply parentheses
-6b-4b-6
We add all the numbers together, and all the variables
-10b-6
Back to the equation:
-(-10b-6)
We get rid of parentheses
-16b+10b+6+24=0
We add all the numbers together, and all the variables
-6b+30=0
We move all terms containing b to the left, all other terms to the right
-6b=-30
b=-30/-6
b=+5

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