8(3-2b)=-2(3+2b)-6b

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Solution for 8(3-2b)=-2(3+2b)-6b equation: 



8(3-2b)=-2(3+2b)-6b

We move all terms to the left:

8(3-2b)-(-2(3+2b)-6b)=0

We add all the numbers together, and all the variables

8(-2b+3)-(-2(2b+3)-6b)=0

We multiply parentheses

-16b-(-2(2b+3)-6b)+24=0



We calculate terms in parentheses: -(-2(2b+3)-6b), so:

-2(2b+3)-6b

We add all the numbers together, and all the variables

-6b-2(2b+3)

We multiply parentheses

-6b-4b-6

We add all the numbers together, and all the variables

-10b-6

Back to the equation:

-(-10b-6)



We get rid of parentheses

-16b+10b+6+24=0

We add all the numbers together, and all the variables

-6b+30=0

We move all terms containing b to the left, all other terms to the right

-6b=-30

b=-30/-6

b=+5

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