8(3-6c)=32

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Solution for 8(3-6c)=32 equation: 



8(3-6c)=32

We move all terms to the left:

8(3-6c)-(32)=0

We add all the numbers together, and all the variables

8(-6c+3)-32=0

We multiply parentheses

-48c+24-32=0

We add all the numbers together, and all the variables

-48c-8=0

We move all terms containing c to the left, all other terms to the right

-48c=8

c=8/-48

c=-1/6

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