8(3-c)=7(c-6)

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Solution for 8(3-c)=7(c-6) equation: 



8(3-c)=7(c-6)

We move all terms to the left:

8(3-c)-(7(c-6))=0

We add all the numbers together, and all the variables

8(-1c+3)-(7(c-6))=0

We multiply parentheses

-8c-(7(c-6))+24=0



We calculate terms in parentheses: -(7(c-6)), so:

7(c-6)

We multiply parentheses

7c-42

Back to the equation:

-(7c-42)



We get rid of parentheses

-8c-7c+42+24=0

We add all the numbers together, and all the variables

-15c+66=0

We move all terms containing c to the left, all other terms to the right

-15c=-66

c=-66/-15

c=4+2/5

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