8(3-x)+2(x+1)=10

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Solution for 8(3-x)+2(x+1)=10 equation: 



8(3-x)+2(x+1)=10

We move all terms to the left:

8(3-x)+2(x+1)-(10)=0

We add all the numbers together, and all the variables

8(-1x+3)+2(x+1)-10=0

We multiply parentheses

-8x+2x+24+2-10=0

We add all the numbers together, and all the variables

-6x+16=0

We move all terms containing x to the left, all other terms to the right

-6x=-16

x=-16/-6

x=2+2/3

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