8(3b+1)=4(b+3)-4

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Solution for 8(3b+1)=4(b+3)-4 equation:



8(3b+1)=4(b+3)-4
We move all terms to the left:
8(3b+1)-(4(b+3)-4)=0
We multiply parentheses
24b-(4(b+3)-4)+8=0
We calculate terms in parentheses: -(4(b+3)-4), so:
4(b+3)-4
We multiply parentheses
4b+12-4
We add all the numbers together, and all the variables
4b+8
Back to the equation:
-(4b+8)
We get rid of parentheses
24b-4b-8+8=0
We add all the numbers together, and all the variables
20b=0
b=0/20
b=0

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