8(3c-5)=(c-8)-1

Solution for 8(3c-5)=(c-8)-1 equation:

8(3c-5)=(c-8)-1

We move all terms to the left:

8(3c-5)-((c-8)-1)=0

We multiply parentheses

24c-((c-8)-1)-40=0


We calculate terms in parentheses: -((c-8)-1), so:

(c-8)-1

We get rid of parentheses

c-8-1

We add all the numbers together, and all the variables

c-9

Back to the equation:

-(c-9)


We get rid of parentheses

24c-c+9-40=0

We add all the numbers together, and all the variables

23c-31=0

We move all terms containing c to the left, all other terms to the right

23c=31

c=31/23

c=1+8/23