8(3f+4)-9f=7(3f+2)10

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Solution for 8(3f+4)-9f=7(3f+2)10 equation: 



8(3f+4)-9f=7(3f+2)10

We move all terms to the left:

8(3f+4)-9f-(7(3f+2)10)=0

We add all the numbers together, and all the variables

-9f+8(3f+4)-(7(3f+2)10)=0

We multiply parentheses

-9f+24f-(7(3f+2)10)+32=0



We calculate terms in parentheses: -(7(3f+2)10), so:

7(3f+2)10

We multiply parentheses

210f+140

Back to the equation:

-(210f+140)



We add all the numbers together, and all the variables

15f-(210f+140)+32=0

We get rid of parentheses

15f-210f-140+32=0

We add all the numbers together, and all the variables

-195f-108=0

We move all terms containing f to the left, all other terms to the right

-195f=108

f=108/-195

f=-36/65

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