8(3k+4)=4(2k-1)

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Solution for 8(3k+4)=4(2k-1) equation: 



8(3k+4)=4(2k-1)

We move all terms to the left:

8(3k+4)-(4(2k-1))=0

We multiply parentheses

24k-(4(2k-1))+32=0



We calculate terms in parentheses: -(4(2k-1)), so:

4(2k-1)

We multiply parentheses

8k-4

Back to the equation:

-(8k-4)



We get rid of parentheses

24k-8k+4+32=0

We add all the numbers together, and all the variables

16k+36=0

We move all terms containing k to the left, all other terms to the right

16k=-36

k=-36/16

k=-2+1/4

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