8(3k-8)+4(k-2)=40

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Solution for 8(3k-8)+4(k-2)=40 equation: 



8(3k-8)+4(k-2)=40

We move all terms to the left:

8(3k-8)+4(k-2)-(40)=0

We multiply parentheses

24k+4k-64-8-40=0

We add all the numbers together, and all the variables

28k-112=0

We move all terms containing k to the left, all other terms to the right

28k=112

k=112/28

k=4

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