8(3n+2)=7(6n+2)+1

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Solution for 8(3n+2)=7(6n+2)+1 equation: 



8(3n+2)=7(6n+2)+1

We move all terms to the left:

8(3n+2)-(7(6n+2)+1)=0

We multiply parentheses

24n-(7(6n+2)+1)+16=0



We calculate terms in parentheses: -(7(6n+2)+1), so:

7(6n+2)+1

We multiply parentheses

42n+14+1

We add all the numbers together, and all the variables

42n+15

Back to the equation:

-(42n+15)



We get rid of parentheses

24n-42n-15+16=0

We add all the numbers together, and all the variables

-18n+1=0

We move all terms containing n to the left, all other terms to the right

-18n=-1

n=-1/-18

n=1/18

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