8(3u+1)=4(b+3)-9

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Solution for 8(3u+1)=4(b+3)-9 equation:


Simplifying
8(3u + 1) = 4(b + 3) + -9

Reorder the terms:
8(1 + 3u) = 4(b + 3) + -9
(1 * 8 + 3u * 8) = 4(b + 3) + -9
(8 + 24u) = 4(b + 3) + -9

Reorder the terms:
8 + 24u = 4(3 + b) + -9
8 + 24u = (3 * 4 + b * 4) + -9
8 + 24u = (12 + 4b) + -9

Reorder the terms:
8 + 24u = 12 + -9 + 4b

Combine like terms: 12 + -9 = 3
8 + 24u = 3 + 4b

Solving
8 + 24u = 3 + 4b

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 24u = 3 + -8 + 4b

Combine like terms: 8 + -8 = 0
0 + 24u = 3 + -8 + 4b
24u = 3 + -8 + 4b

Combine like terms: 3 + -8 = -5
24u = -5 + 4b

Divide each side by '24'.
u = -0.2083333333 + 0.1666666667b

Simplifying
u = -0.2083333333 + 0.1666666667b

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