8(3x-2)-14x=2(4-7x)+15x=

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Solution for 8(3x-2)-14x=2(4-7x)+15x= equation: 



8(3x-2)-14x=2(4-7x)+15x=

We move all terms to the left:

8(3x-2)-14x-(2(4-7x)+15x)=0

We add all the numbers together, and all the variables

8(3x-2)-14x-(2(-7x+4)+15x)=0

We add all the numbers together, and all the variables

-14x+8(3x-2)-(2(-7x+4)+15x)=0

We multiply parentheses

-14x+24x-(2(-7x+4)+15x)-16=0



We calculate terms in parentheses: -(2(-7x+4)+15x), so:

2(-7x+4)+15x

We add all the numbers together, and all the variables

15x+2(-7x+4)

We multiply parentheses

15x-14x+8

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We add all the numbers together, and all the variables

10x-(x+8)-16=0

We get rid of parentheses

10x-x-8-16=0

We add all the numbers together, and all the variables

9x-24=0

We move all terms containing x to the left, all other terms to the right

9x=24

x=24/9

x=2+2/3

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