8(3x-2)-2(x-3)=4(4x+5)+18

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Solution for 8(3x-2)-2(x-3)=4(4x+5)+18 equation:



8(3x-2)-2(x-3)=4(4x+5)+18
We move all terms to the left:
8(3x-2)-2(x-3)-(4(4x+5)+18)=0
We multiply parentheses
24x-2x-(4(4x+5)+18)-16+6=0
We calculate terms in parentheses: -(4(4x+5)+18), so:
4(4x+5)+18
We multiply parentheses
16x+20+18
We add all the numbers together, and all the variables
16x+38
Back to the equation:
-(16x+38)
We add all the numbers together, and all the variables
22x-(16x+38)-10=0
We get rid of parentheses
22x-16x-38-10=0
We add all the numbers together, and all the variables
6x-48=0
We move all terms containing x to the left, all other terms to the right
6x=48
x=48/6
x=8

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