8(3x-2)-20x=2(x-6)-12

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Solution for 8(3x-2)-20x=2(x-6)-12 equation: 



8(3x-2)-20x=2(x-6)-12

We move all terms to the left:

8(3x-2)-20x-(2(x-6)-12)=0

We add all the numbers together, and all the variables

-20x+8(3x-2)-(2(x-6)-12)=0

We multiply parentheses

-20x+24x-(2(x-6)-12)-16=0



We calculate terms in parentheses: -(2(x-6)-12), so:

2(x-6)-12

We multiply parentheses

2x-12-12

We add all the numbers together, and all the variables

2x-24

Back to the equation:

-(2x-24)



We add all the numbers together, and all the variables

4x-(2x-24)-16=0

We get rid of parentheses

4x-2x+24-16=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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