8(3y+2)-12(3y-5)=64

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Solution for 8(3y+2)-12(3y-5)=64 equation: 



8(3y+2)-12(3y-5)=64

We move all terms to the left:

8(3y+2)-12(3y-5)-(64)=0

We multiply parentheses

24y-36y+16+60-64=0

We add all the numbers together, and all the variables

-12y+12=0

We move all terms containing y to the left, all other terms to the right

-12y=-12

y=-12/-12

y=1

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