8(3y-2)=3(10-y)+35

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Solution for 8(3y-2)=3(10-y)+35 equation: 



8(3y-2)=3(10-y)+35

We move all terms to the left:

8(3y-2)-(3(10-y)+35)=0

We add all the numbers together, and all the variables

8(3y-2)-(3(-1y+10)+35)=0

We multiply parentheses

24y-(3(-1y+10)+35)-16=0



We calculate terms in parentheses: -(3(-1y+10)+35), so:

3(-1y+10)+35

We multiply parentheses

-3y+30+35

We add all the numbers together, and all the variables

-3y+65

Back to the equation:

-(-3y+65)



We get rid of parentheses

24y+3y-65-16=0

We add all the numbers together, and all the variables

27y-81=0

We move all terms containing y to the left, all other terms to the right

27y=81

y=81/27

y=3

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