8(4+2)+3=2(3y-4)-y

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Solution for 8(4+2)+3=2(3y-4)-y equation:



8(4+2)+3=2(3y-4)-y
We move all terms to the left:
8(4+2)+3-(2(3y-4)-y)=0
We add all the numbers together, and all the variables
-(2(3y-4)-y)+3+86=0
We add all the numbers together, and all the variables
-(2(3y-4)-y)+89=0
We calculate terms in parentheses: -(2(3y-4)-y), so:
2(3y-4)-y
We add all the numbers together, and all the variables
-1y+2(3y-4)
We multiply parentheses
-1y+6y-8
We add all the numbers together, and all the variables
5y-8
Back to the equation:
-(5y-8)
We get rid of parentheses
-5y+8+89=0
We add all the numbers together, and all the variables
-5y+97=0
We move all terms containing y to the left, all other terms to the right
-5y=-97
y=-97/-5
y=19+2/5

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