8(4+4m)=10(m-8)+2

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Solution for 8(4+4m)=10(m-8)+2 equation: 



8(4+4m)=10(m-8)+2

We move all terms to the left:

8(4+4m)-(10(m-8)+2)=0

We add all the numbers together, and all the variables

8(4m+4)-(10(m-8)+2)=0

We multiply parentheses

32m-(10(m-8)+2)+32=0



We calculate terms in parentheses: -(10(m-8)+2), so:

10(m-8)+2

We multiply parentheses

10m-80+2

We add all the numbers together, and all the variables

10m-78

Back to the equation:

-(10m-78)



We get rid of parentheses

32m-10m+78+32=0

We add all the numbers together, and all the variables

22m+110=0

We move all terms containing m to the left, all other terms to the right

22m=-110

m=-110/22

m=-5

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