8(4+x)-8=8(3-x)+16x

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Solution for 8(4+x)-8=8(3-x)+16x equation: 



8(4+x)-8=8(3-x)+16x

We move all terms to the left:

8(4+x)-8-(8(3-x)+16x)=0

We add all the numbers together, and all the variables

8(x+4)-(8(-1x+3)+16x)-8=0

We multiply parentheses

8x-(8(-1x+3)+16x)+32-8=0



We calculate terms in parentheses: -(8(-1x+3)+16x), so:

8(-1x+3)+16x

We add all the numbers together, and all the variables

16x+8(-1x+3)

We multiply parentheses

16x-8x+24

We add all the numbers together, and all the variables

8x+24

Back to the equation:

-(8x+24)



We add all the numbers together, and all the variables

8x-(8x+24)+24=0

We get rid of parentheses

8x-8x-24+24=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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