8(4+y)=7(y-3)

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Solution for 8(4+y)=7(y-3) equation:


Simplifying
8(4 + y) = 7(y + -3)
(4 * 8 + y * 8) = 7(y + -3)
(32 + 8y) = 7(y + -3)

Reorder the terms:
32 + 8y = 7(-3 + y)
32 + 8y = (-3 * 7 + y * 7)
32 + 8y = (-21 + 7y)

Solving
32 + 8y = -21 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
32 + 8y + -7y = -21 + 7y + -7y

Combine like terms: 8y + -7y = 1y
32 + 1y = -21 + 7y + -7y

Combine like terms: 7y + -7y = 0
32 + 1y = -21 + 0
32 + 1y = -21

Add '-32' to each side of the equation.
32 + -32 + 1y = -21 + -32

Combine like terms: 32 + -32 = 0
0 + 1y = -21 + -32
1y = -21 + -32

Combine like terms: -21 + -32 = -53
1y = -53

Divide each side by '1'.
y = -53

Simplifying
y = -53

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