8(4-28x)=4(3-5x)+4x

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Solution for 8(4-28x)=4(3-5x)+4x equation: 



8(4-28x)=4(3-5x)+4x

We move all terms to the left:

8(4-28x)-(4(3-5x)+4x)=0

We add all the numbers together, and all the variables

8(-28x+4)-(4(-5x+3)+4x)=0

We multiply parentheses

-224x-(4(-5x+3)+4x)+32=0



We calculate terms in parentheses: -(4(-5x+3)+4x), so:

4(-5x+3)+4x

We add all the numbers together, and all the variables

4x+4(-5x+3)

We multiply parentheses

4x-20x+12

We add all the numbers together, and all the variables

-16x+12

Back to the equation:

-(-16x+12)



We get rid of parentheses

-224x+16x-12+32=0

We add all the numbers together, and all the variables

-208x+20=0

We move all terms containing x to the left, all other terms to the right

-208x=-20

x=-20/-208

x=5/52

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