8(4-2k)=128

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Solution for 8(4-2k)=128 equation: 



8(4-2k)=128

We move all terms to the left:

8(4-2k)-(128)=0

We add all the numbers together, and all the variables

8(-2k+4)-128=0

We multiply parentheses

-16k+32-128=0

We add all the numbers together, and all the variables

-16k-96=0

We move all terms containing k to the left, all other terms to the right

-16k=96

k=96/-16

k=-6

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