8(4-2x)=2(3x-4)

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Solution for 8(4-2x)=2(3x-4) equation: 



8(4-2x)=2(3x-4)

We move all terms to the left:

8(4-2x)-(2(3x-4))=0

We add all the numbers together, and all the variables

8(-2x+4)-(2(3x-4))=0

We multiply parentheses

-16x-(2(3x-4))+32=0



We calculate terms in parentheses: -(2(3x-4)), so:

2(3x-4)

We multiply parentheses

6x-8

Back to the equation:

-(6x-8)



We get rid of parentheses

-16x-6x+8+32=0

We add all the numbers together, and all the variables

-22x+40=0

We move all terms containing x to the left, all other terms to the right

-22x=-40

x=-40/-22

x=1+9/11

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