8(4-2x)=4(3-5x)+2x

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Solution for 8(4-2x)=4(3-5x)+2x equation: 



8(4-2x)=4(3-5x)+2x

We move all terms to the left:

8(4-2x)-(4(3-5x)+2x)=0

We add all the numbers together, and all the variables

8(-2x+4)-(4(-5x+3)+2x)=0

We multiply parentheses

-16x-(4(-5x+3)+2x)+32=0



We calculate terms in parentheses: -(4(-5x+3)+2x), so:

4(-5x+3)+2x

We add all the numbers together, and all the variables

2x+4(-5x+3)

We multiply parentheses

2x-20x+12

We add all the numbers together, and all the variables

-18x+12

Back to the equation:

-(-18x+12)



We get rid of parentheses

-16x+18x-12+32=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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