8(4-2x)=4(3-5x)+5x

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Solution for 8(4-2x)=4(3-5x)+5x equation: 



8(4-2x)=4(3-5x)+5x

We move all terms to the left:

8(4-2x)-(4(3-5x)+5x)=0

We add all the numbers together, and all the variables

8(-2x+4)-(4(-5x+3)+5x)=0

We multiply parentheses

-16x-(4(-5x+3)+5x)+32=0



We calculate terms in parentheses: -(4(-5x+3)+5x), so:

4(-5x+3)+5x

We add all the numbers together, and all the variables

5x+4(-5x+3)

We multiply parentheses

5x-20x+12

We add all the numbers together, and all the variables

-15x+12

Back to the equation:

-(-15x+12)



We get rid of parentheses

-16x+15x-12+32=0

We add all the numbers together, and all the variables

-1x+20=0

We move all terms containing x to the left, all other terms to the right

-x=-20

x=-20/-1

x=+20

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