8(4-2x)=4(3-5x)4x

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Solution for 8(4-2x)=4(3-5x)4x equation: 



8(4-2x)=4(3-5x)4x

We move all terms to the left:

8(4-2x)-(4(3-5x)4x)=0

We add all the numbers together, and all the variables

8(-2x+4)-(4(-5x+3)4x)=0

We multiply parentheses

-16x-(4(-5x+3)4x)+32=0



We calculate terms in parentheses: -(4(-5x+3)4x), so:

4(-5x+3)4x

We multiply parentheses

-80x^2+48x

Back to the equation:

-(-80x^2+48x)



We get rid of parentheses

80x^2-48x-16x+32=0

We add all the numbers together, and all the variables

80x^2-64x+32=0

a = 80; b = -64; c = +32;
Δ = b2-4ac
Δ = -642-4·80·32
Δ = -6144
Delta is less than zero, so there is no solution for the equation

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