8(4-2x)=4(3-5x)=4x

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Solution for 8(4-2x)=4(3-5x)=4x equation: 



8(4-2x)=4(3-5x)=4x

We move all terms to the left:

8(4-2x)-(4(3-5x))=0

We add all the numbers together, and all the variables

8(-2x+4)-(4(-5x+3))=0

We multiply parentheses

-16x-(4(-5x+3))+32=0



We calculate terms in parentheses: -(4(-5x+3)), so:

4(-5x+3)

We multiply parentheses

-20x+12

Back to the equation:

-(-20x+12)



We get rid of parentheses

-16x+20x-12+32=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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